A) 58
B) 142
C) 104
D) -104
Correct Answer: A
Solution :
We have, \[3x-7y=10~~~~~~...(i)\] And \[xy=-1~~~~~~~~~~...(ii)\] Squaring both sides of (i), we get \[{{(3x)}^{2}}+{{(7y)}^{2}}-2\times 3x\times 7y={{10}^{2}}\] or \[9{{x}^{2}}+49{{y}^{2}}-42xy=100\] or \[9{{x}^{2}}+49{{y}^{2}}-42(-1)=100\] (Using (i)) \[\therefore \] \[9{{x}^{2}}+49{{y}^{2}}=100-42=58\]You need to login to perform this action.
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