6th Class Mathematics Algebra Question Bank Algebra

  • question_answer
    The product of the polynomials, \[(3{{u}^{2}}v-5u{{v}^{2}})\] and \[\left( \frac{1}{5}{{u}^{2}}+\frac{1}{5}{{v}^{2}} \right)\] is

    A)  \[\frac{3}{5}{{u}^{4}}v-{{u}^{3}}{{v}^{2}}-u{{v}^{4}}+\frac{3}{5}{{u}^{2}}{{v}^{3}}\]

    B)  \[\frac{{{u}^{4}}v}{5}-2u{{v}^{2}}\,+{{u}^{2}}{{v}^{3}}\,-\frac{5u{{v}^{4}}}{3}\]

    C)  \[\frac{3{{u}^{4}}v}{5}-4{{v}^{2}}+4{{u}^{2}}{{v}^{3}}-\frac{5u{{v}^{4}}}{3}\]

    D)  \[\frac{3{{u}^{4}}v}{5}-{{u}^{3}}{{v}^{2}}+{{u}^{2}}{{v}^{3}}-5u{{v}^{4}}\]

    Correct Answer: A

    Solution :

         Product \[=(3{{u}^{2}}v-5u{{v}^{2}})\,\left( \frac{1}{5}{{u}^{2}}+\frac{1}{5}{{v}^{2}} \right)\] \[=3{{u}^{2}}v\,\left( \frac{1}{5}{{u}^{2}}+\frac{1}{5}{{v}^{2}} \right)\,-5u{{v}^{2}}\] \[\left( \frac{1}{5}\,{{u}^{2}}+\frac{1}{5}{{v}^{2}} \right)\] \[=\frac{3}{5}{{u}^{4}}v+\frac{3}{5}\,{{u}^{2}}{{v}^{3}}-{{u}^{3}}{{v}^{2}}-u{{v}^{4}}\]


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