A) \[\pm 8\]
B) \[\pm 6\]
C) \[\pm 7\]
D) \[\pm 5\]
Correct Answer: A
Solution :
\[4x+{{y}^{2}}=40\] Now, \[{{\left( 2x \right)}^{2}}+{{\left( y \right)}^{2}}=40\] Adding, 4xy both sides, \[{{\left( 2x \right)}^{2}}+{{\left( y \right)}^{2}}+2.2x.y=40+4xy\] \[{{\left( 2x+y \right)}^{2}}=40+4\times 6\] Therefore, \[2x+y=\pm \sqrt{64}=\pm 8\]
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