6th Class Mathematics Algebra Question Bank Algebra

  • question_answer
    If\[A=\frac{9{{x}^{4}}-3{{x}^{3}}-6{{x}^{2}}-9x}{3x},\] \[B=\frac{18{{x}^{4}}+12{{x}^{3}}+6{{x}^{2}}+9x}{3x}\]then \[B-A\] is

    A)  \[3{{x}^{2}}-5{{x}^{2}}-4x+6\]           

    B)  \[3{{x}^{3}}+5{{x}^{2}}+4x+6\]

    C)  \[3{{x}^{3}}-5{{x}^{2}}-4x-6\] 

    D) \[3{{x}^{3}}+5{{x}^{2}}-4x-6\]

    Correct Answer: B

    Solution :

    \[A=\frac{9{{x}^{4}}}{3x}-\frac{3{{x}^{3}}}{3x}-\frac{6{{x}^{2}}}{3x}-\frac{9x}{3x}\] \[=3{{x}^{3}}-{{x}^{2}}-2x-3\] \[B-A=\left( 6{{x}^{3}}+4{{x}^{2}}+2x+3 \right)-\left( 3{{x}^{3}}-{{x}^{2}}-2x-3 \right)\]\[=6{{x}^{3}}-3{{x}^{3}}+4{{x}^{2}}+{{x}^{2}}+2x+2x+3+3\] \[=3{{x}^{3}}+5{{x}^{2}}+4x+6\]


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