6th Class Mathematics Algebra Question Bank Algebra

  • question_answer
    If \[(3x-4)(5x+7)=15{{x}^{2}}-ax-28a\] then\[a=\]?

    A)  1

    B)  \[-1\]

    C) \[-3\]

    D)  4

    Correct Answer: B

    Solution :

    \[(3x-4)\left( 5x+7 \right)=15{{x}^{2}}-ax-28.\] \[15{{x}^{2}}+21x-20x-28=15{{x}^{2}}-ax-28\] \[\Rightarrow \]\[15{{x}^{2}}+x-28=15{{x}^{2}}+ax-28\] \[\Rightarrow \]\[x=-ax\] \[\therefore \]\[a=\frac{x}{-x}=-1\] \[\therefore \]\[a=-1\]


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