A B C D
A) 1 2 3 4
B) 3 1 4 2
C) 2 1 3 4
D) 3 1 2 4
Correct Answer: D
Solution :
(A) \[{{(x-5)}^{2}}-{{(x+3)}^{2}}=48\] \[{{x}^{2}}+25-10x-{{x}^{2}}-9-6x=48\] \[\Rightarrow \,\,-16x+16=48\Rightarrow x=-2\] (B) \[(2x-1)\,(2x+3)=(4{{x}^{2}}-49)\] \[\Rightarrow \,\,4{{x}^{2}}+6x-2x-3=4{{x}^{2}}-49\] \[\Rightarrow \,\,4x-3+49=0\] \[\Rightarrow \,\,x=-\frac{46}{4}=-\frac{23}{2}=-11\frac{1}{2}\] (C) \[14-\frac{x-1}{10}=\frac{x+5}{6}-3\] \[\Rightarrow \,\,14+3=\frac{x+5}{6}+\frac{x-1}{10}\] \[\Rightarrow \,\,17=\frac{10x+50+6x-6}{60}\] \[\Rightarrow \,\,17\times 60-44=16x\] \[\Rightarrow \,\,x=\frac{1020-44}{16}=61\] (D) \[6(x-4)=4(x-3)-(3x-8)\] \[\Rightarrow \,\,6x-24=4x-12-3x+8\] \[\Rightarrow \,\,5x=20\] \[\Rightarrow \,\,x=4\]
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