A B C D
A) 3 1 2 4
B) 3 1 4 2
C) 1 2 3 4
D) 1 3 2 4
Correct Answer: B
Solution :
(A) \[{{({{3}^{3}})}^{2}}={{({{3}^{2}})}^{3}}={{(9)}^{3}}\] (B) \[{{({{0}^{6}})}^{12}}={{({{0}^{18}})}^{15}}=0\] (C) \[{{({{644}^{3}})}^{0}}=1\]and\[{{({{3}^{0}})}^{644}}={{(1)}^{644}}=1\] (D) \[{{({{2}^{2}})}^{6}}={{(4)}^{6}}=4\times 4\times 4\times 4\times 4\times 4\] \[=16\times 16\times 16={{(16)}^{3}}\]
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