7th Class Mathematics Algebraic Expressions Question Bank Algebra

  • question_answer
    The multiplicative inverse of\[{{(16)}^{2}}\]is

    A)  \[{{(16)}^{1}}\]                 

    B)  \[{{(16)}^{-2}}\]

    C)  \[{{(16)}^{-3}}\]                            

    D)  \[1\]

    Correct Answer: B

    Solution :

    multiplicative inverse\[=\frac{1}{{{(16)}^{2}}}={{(16)}^{-2}}\]


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