A) \[\frac{9}{17}\]
B) \[\frac{17}{9}\]
C) \[\frac{17}{10}\]
D) \[\frac{20}{9}\]
Correct Answer: B
Solution :
\[{{({{2}^{6}})}^{2x-5}}={{2}^{2}}\times {{({{2}^{3}})}^{x-5}}\] or \[12x-30=2+3x-15\] or \[9x=17\] or \[x=\frac{17}{9}\]
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