A) 16
B) 9
C) 4
D) 1
Correct Answer: B
Solution :
\[2x+y=3\] or \[{{(2x+y)}^{3}}=27\] or \[8{{x}^{3}}+{{y}^{3}}+6xy(2x+y)=27\] or \[8{{x}^{3}}+{{y}^{3}}+6\times 1\times 3=27\] or \[8{{x}^{3}}+{{y}^{3}}=9\]
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