10th Class Mathematics Related to Competitive Exam Question Bank Algebra

  • question_answer
    The largest angle of a triangle is twice the sum of the other two and the smallest one is one fourth of the largest. The agles are

    A) \[120{}^\circ ,\text{ }40{}^\circ ,\text{ }20{}^\circ \]   

    B)        \[120{}^\circ ,\text{ }30{}^\circ ,\text{ }30{}^\circ \]  

    C) \[90{}^\circ ,\text{ }45{}^\circ ,\text{ }45{}^\circ \]

    D)        \[~90{}^\circ ,\text{ }60{}^\circ ,\text{ }30{}^\circ \]

    Correct Answer: B

    Solution :

     Let the angles be \[x,\,\,y,\,\,z\] (\[x\] is largest and \[z\] is smallest) Then\[,\]             \[x+y+z={{180}^{o}}\]                                    ? (i)                 \[x=2(y+z)\] or            \[2x=4y+4z\]                                      ? (ii) and        \[z=\frac{x}{4}\] or            \[x=4z\]                                                               ? (iii) From equations (ii) and (iii), we get                 \[x=4y\]                                                               ? (iv) From equations (iii) and (iv), we get                 \[y=z\]                                                  ? (v) From equations (i), (iii) and (iv), we get                 \[4z+z+z={{180}^{o}}\] or            \[z={{30}^{o}}\] Hence angles are\[{{120}^{o}},\,\,{{30}^{o}},\,\,{{30}^{o}}\]


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