A) - 3
B) 3
C) 6
D) - 6
Correct Answer: A
Solution :
Let \[\alpha ,\,\,\beta \] be the roots of the equation, \[{{x}^{2}}+2x-p=0\] Then \[\alpha +\beta =-2\], and \[\alpha \beta =-p\] By hypothesis \[{{\alpha }^{2}}+{{\beta }^{2}}=10\] or \[{{(\alpha +\beta )}^{2}}-2\alpha \beta =10\] or \[{{(-2)}^{2}}-2(-p)=10\] or \[4+2p=10\] or \[2p=-6\] \[\therefore \] \[p=-3\]
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