A) 4 and 5
B) 1 and 8
C) 3 and 6
D) 2 and 7
Correct Answer: A
Solution :
Let the numbers are \[x\] and\[y\]. Then by hypothesis \[x+y=9\] ? (i) \[{{x}^{2}}+{{y}^{2}}=41\] ? (ii) Substituting this value in equation (i), we get \[{{x}^{2}}+{{(9-x)}^{2}}=41\] or \[{{x}^{2}}+81-18x+{{x}^{2}}=41\] or \[2{{x}^{2}}-18x+40=0\] or \[{{x}^{2}}-9x+20=0\] or \[(x-5)(x-4)=0\] \[\therefore \] \[x=5\]or\[x=4\] Then \[y=9-x=9-5=4\] or \[y=9-4=5\]
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