A) \[\frac{1}{8}\]
B) \[-\frac{1}{8}\]
C) \[\frac{8}{3}\]
D) \[-\frac{8}{3}\]
Correct Answer: B
Solution :
Given \[\frac{2x+3}{2x-1}=\frac{3x-1}{3x+1}\] By dividend \[\frac{2x+3}{(2x+3)-(2x-1)}\] \[=\frac{3x-1}{(3x-1)-(3x+1)}\] or \[\frac{2x+3}{4}=\frac{3x-1}{-2}\] or \[2x+3=-6x+2\] or \[8x=-1\] \[\therefore \] \[x=-\frac{1}{8}\]You need to login to perform this action.
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