A) \[x+y\]
B) \[y+z\]
C) \[(x+y)(y+z)(z+x)\]
D) \[{{x}^{2}}+{{y}^{2}}\]
Correct Answer: C
Solution :
\[xy+yz+zx+{{y}^{2}}=(xy+{{y}^{2}})(yz+zx)\] \[=y(x+y)+z(y+x)\] \[=(x+y)(y+z)\] and \[{{x}^{2}}+xy+yz+zx=x(x+y)+z(y+x)\] \[=(x+y)(x+z)=(x+y)(z+x)\] \[\therefore \] \[L.C.M.=(x+y)(y+z)(z+x)\]
You need to login to perform this action.
You will be redirected in
3 sec
