A) \[C{{H}_{3}}COONa\]
B) \[N{{H}_{4}}Cl\]
C) \[NaCl\]
D) \[C{{H}_{3}}COON{{H}_{4}}\]
Correct Answer: B
Solution :
\[N{{H}_{4}}Cl+{{H}_{2}}O\]⇌\[\underset{\text{Weak}\,\,\,\text{base}}{\mathop{N{{H}_{4}}OH}}\,+\underset{\text{Strong}\,\,\,\text{acid}}{\mathop{HCl}}\,\]. So it is acidic in nature.
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