JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Question Bank Acids and Bases

  • question_answer
    The salt that forms neutral solution in water is [EAMCET 1981]

    A)                 \[N{{H}_{4}}Cl\]               

    B)                 \[NaCl\]

    C)                 \[N{{a}_{2}}C{{O}_{3}}\]              

    D)                 \[{{K}_{3}}B{{O}_{3}}\]

    Correct Answer: B

    Solution :

               Because it is a salt of strong acid and strong base. \[{{H}^{+}}_{\text{(aq)}}+C{{l}^{-}}_{\text{(aq)}}+N{{a}^{+}}_{\text{(aq)}}+O{{H}^{-}}_{\text{(aq)}}\] ⇌                                                                         \[{{H}_{2}}{{O}_{\text{(l)}}}+N{{a}^{+}}_{\text{(aq)}}+C{{l}^{-}}\]


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