A) \[HN{{O}_{3}}\]
B) \[HCl{{O}_{4}}\]
C) \[{{H}_{2}}S{{O}_{4}}\]
D) \[HBr\]
Correct Answer: A
Solution :
\[\underset{\text{Aciedic character decreases }}{\mathop{HCl{{O}_{4}}>{{H}_{2}}S{{O}_{4}}>HCl>HN{{O}_{3}}}}\,\].
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