JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Question Bank Acids and Bases

  • question_answer
    \[p{{K}_{a}}\] of a weak acid is defined as            [JIPMER 1999]

    A)                 log\[_{10}{{K}_{a}}\]     

    B)                 \[\frac{1}{lo{{g}_{10}}{{K}_{a}}}\]

    C)                 log \[_{10}\frac{1}{{{K}_{a}}}\]  

    D)                 ?log \[_{10}\frac{1}{{{K}_{a}}}\]

    Correct Answer: C

    Solution :

                    \[p{{K}_{a}}={{\log }_{10}}\frac{1}{{{K}_{a}}}\]


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