A) \[N{{H}_{4}}Cl\]gives alkaline solution in water
B) \[C{{H}_{3}}COONa\] gives acidic solution in water
C) \[C{{H}_{3}}COOH\] is a weak acid
D) \[N{{H}_{4}}OH\] is a strong base
Correct Answer: C
Solution :
\[C{{H}_{3}}COOH\] is weak acid shows dissociation equilibrium as \[C{{H}_{3}}COOH\]⇌\[C{{H}_{3}}CO{{O}^{-}}+{{H}^{+}}\]
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