A) \[{{H}_{3}}P{{O}_{4}}\]
B) \[{{H}_{3}}P{{O}_{3}}\]
C) \[{{H}_{2}}PO_{3}^{-}\]
D) \[PO_{4}^{3-}\]
Correct Answer: C
Solution :
\[\underset{\text{Conjugate acid}}{\mathop{{{H}_{2}}PO_{4}^{-}}}\,\]⇌ \[{{H}^{+}}+HPO{{_{4}^{2}}^{-}}\]action.
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