question_answer

Accepting the definition that an acid is a proton donor, the acid in the following reaction \[N{{H}_{3}}+{{H}_{2}}O\to NH_{4}^{+}+O{{H}^{-}}\] is          [Kerala (Med.) 2003]

A)                 \[N{{H}_{3}}\]  

B)                 \[{{H}^{+}}\]

C)                 \[NH_{4}^{+}\]

D)                 \[{{H}_{2}}O\]