A) Ammonium hydroxide
B) Chloroform
C) Benzene
D) Water
Correct Answer: D
Solution :
\[\underset{\text{Acid}}{\mathop{{{H}_{2}}O}}\,\to {{H}^{+}}+O{{H}^{-}}\][Acid due to donation of proton] \[\underset{\text{Base}}{\mathop{{{H}_{2}}O}}\,+{{H}^{+}}\to {{H}_{3}}{{O}^{+}}\][Basic due to gaining of proton]
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