question_answer1) In the given figure, the area of the \[\Delta ABC\] is
A) \[13.24\,c{{m}^{2}}\] done clear
B) \[~12.28\,c{{m}^{2}}\] done clear
C) \[~11.32\,c{{m}^{2}}\] done clear
D) \[~15.37\,c{{m}^{2}}\] done clear
View Solution play_arrowA) \[20\sqrt{7}\,c{{m}^{2}}\] done clear
B) \[10\sqrt{14}\,c{{m}^{2}}\] done clear
C) \[20\sqrt{14}\,c{{m}^{2}}\] done clear
D) \[140\,c{{m}^{2}}\] done clear
View Solution play_arrowA) \[~9100\,{{m}^{2~}}\] done clear
B) \[~9000\,{{m}^{2}}\] done clear
C) \[~9200\,{{m}^{2}}\] done clear
D) \[~9500\,{{m}^{2}}\] done clear
View Solution play_arrowA) \[48\,c{{m}^{2}}\] done clear
B) \[28\sqrt{3}\,c{{m}^{2}}\] done clear
C) \[32\sqrt{2}\,c{{m}^{2}}\] done clear
D) \[44\,c{{m}^{2}}\] done clear
View Solution play_arrowA) \[~1536\,{{m}^{2}}\] done clear
B) \[~1636\,{{m}^{2}}\] done clear
C) \[~1236\,{{m}^{2}}\] done clear
D) \[~1336\,{{m}^{2}}\] done clear
View Solution play_arrowA) 15 cm done clear
B) 14 cm done clear
C) 12 cm done clear
D) 13 cm done clear
View Solution play_arrowA) 3 done clear
B) 4 done clear
C) 2 done clear
D) 5 done clear
View Solution play_arrowA) 18cm done clear
B) 12cm done clear
C) 15cm done clear
D) 25cm done clear
View Solution play_arrowA) ` 880 done clear
B) ` 1020 done clear
C) ` 960 done clear
D) ` 980 done clear
View Solution play_arrowA) 8 done clear
B) 6 done clear
C) 7 done clear
D) 9 done clear
View Solution play_arrowA) 3 cm done clear
B) 6 cm done clear
C) 4 cm done clear
D) 2 cm done clear
View Solution play_arrowA) \[30\sqrt{7}\,cm\] done clear
B) \[\frac{15\sqrt{7}}{2}\,cm\] done clear
C) \[\frac{15\sqrt{7}}{4}\,cm\] done clear
D) \[30\,cm\] done clear
View Solution play_arrowA) \[~196\,c{{m}^{2}}\] done clear
B) \[~186\,c{{m}^{2}}\] done clear
C) \[~169\,c{{m}^{2}}\] done clear
D) \[~199\,c{{m}^{2}}\] done clear
View Solution play_arrowA) ` 9500 done clear
B) ` 11000 done clear
C) ` 10500 done clear
D) ` 12500 done clear
View Solution play_arrowA) 64 cm done clear
B) 46 cm done clear
C) 84 cm done clear
D) 54 cm done clear
View Solution play_arrowA) ` 14.92 done clear
B) ` 14 done clear
C) ` 16 done clear
D) ` 13 done clear
View Solution play_arrowA) \[2104.56\text{ }c{{m}^{2}},\text{ }2104.56\text{ }c{{m}^{2}}\] done clear
B) \[4209.22\text{ }c{{m}^{2}},\,2104.56\text{ }c{{m}^{2}}\] done clear
C) \[1204.61\text{ }c{{m}^{2}},\text{ }1204.61\text{ }c{{m}^{2}}\] done clear
D) \[2014.61\text{ }c{{m}^{2}},1204.61\text{ }c{{m}^{2}}\] done clear
View Solution play_arrowA) \[840\,c{{m}^{2}}\] done clear
B) \[1680\,c{{m}^{2}}\] done clear
C) \[480\,c{{m}^{2}}\] done clear
D) \[7844\,c{{m}^{2}}\] done clear
View Solution play_arrowA) \[98\sqrt{3}\,c{{m}^{2}}\] done clear
B) \[8\sqrt{3}\,c{{m}^{2}}\] done clear
C) \[42\sqrt{3}\,c{{m}^{2}}\] done clear
D) \[36\sqrt{3}\,c{{m}^{2}}\] done clear
View Solution play_arrowA) \[59.86\,c{{m}^{2}}\] done clear
B) \[50\,c{{m}^{2}}\] done clear
C) \[59\,c{{m}^{2}}\] done clear
D) \[53\,c{{m}^{2}}\] done clear
View Solution play_arrowA) \[3\sqrt{3}\,c{{m}^{2}}\] done clear
B) \[2\sqrt{3}\,c{{m}^{2}}\] done clear
C) \[\frac{\sqrt{3}}{2}\,c{{m}^{2}}\] done clear
D) \[\frac{\sqrt{3}}{4}c{{m}^{2}}\] done clear
View Solution play_arrowA) \[1632\,c{{m}^{2}},1886\,c{{m}^{2}}\] done clear
B) \[1538\,c{{m}^{2}},1632\,c{{m}^{2}}\] done clear
C) \[1632\,c{{m}^{2}},1868\,c{{m}^{2}}\] done clear
D) \[1538\,c{{m}^{2}},1632\,c{{m}^{2}}\] done clear
View Solution play_arrowA) X+Z = Y+W done clear
B) W + X = Z done clear
C) Y + Z = X done clear
D) \[X+W=\frac{1}{2}(Y+Z)\] done clear
View Solution play_arrowquestion_answer24) State T for true and 'F' for false.
(i) The lengths of the three sides of a triangular field are 40 m, 24 m and 32 m respectively. The area of the triangle is \[384\text{ }{{m}^{2}}.\] |
(ii) The area of a quadrilateral ABCD in which B = 3 cm, BC= 4 cm, CD =4 cm, DA = 5 cm and AC = 5 cm is \[18\text{ }c{{m}^{2}}.\] |
(iii) An advertisement board is in the form of an isosceles triangle with its sides equal to 12 m, 10 m and 10 m. The cost of painting it at ` 2.25 per \[{{m}^{2}}\]is \[18\text{ }c{{m}^{2}}.\]112. |
(iv) Heron's formula cannot be used to calculate area of quadrilaterals. |
A)
(i) | (ii) | (iii) | (iv) | |
T | F | F | T |
B)
(i) | (ii) | (iii) | (iv) | |
F | T | F | F |
C)
(i) | (ii) | (iii) | (iv) | |
T | F | T | F |
D)
(i) | (ii) | (iii) | (iv) | |
T | F | F | F |
A) \[~300\,c{{m}^{2}}\] done clear
B) \[~180\,c{{m}^{2}}\] done clear
C) \[~126\,c{{m}^{2}}\] done clear
D) \[306\,c{{m}^{2}}\] done clear
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