A) \[r+3=15\] done clear
B) \[15+r=3\] done clear
C) \[3r=15\] done clear
D) \[\frac{3}{r}=15\] done clear
View Solution play_arrowquestion_answer2) The solution of the equation \[10-3y=1\] is y=____.
A) 0 done clear
B) 1 done clear
C) 2 done clear
D) 3 done clear
View Solution play_arrowquestion_answer3) 5 less than thrice a number and add 7. The result is 14. The number is _____.
A) 5 done clear
B) 4 done clear
C) 6 done clear
D) 2 done clear
View Solution play_arrowquestion_answer4) Which of the given equation does not have 4 as the solution?
A) \[p+5=9\] done clear
B) \[14-p=10\] done clear
C) \[\frac{20}{p}=4\] done clear
D) \[9p=36\] done clear
View Solution play_arrowA) 72 done clear
B) 110 done clear
C) 112 done clear
D) 114 done clear
View Solution play_arrowquestion_answer6) If \[\frac{2x}{1+\frac{1}{1+\frac{x}{1-x}}}\] then find the value of x.
A) 1 done clear
B) 4/3 done clear
C) 1/3 done clear
D) 2/3 done clear
View Solution play_arrowA) \[-12\] done clear
B) \[-4\] done clear
C) 4 done clear
D) 12 done clear
View Solution play_arrowA) \[14\frac{2}{97}\] done clear
B) \[16\frac{2}{97}\] done clear
C) \[18\frac{2}{97}\] done clear
D) \[15\frac{2}{97}\] done clear
View Solution play_arrowA) \[{{102}^{o}}\] done clear
B) \[{{65}^{o}}\] done clear
C) \[{{112}^{o}}\] done clear
D) \[{{72}^{o}}\] done clear
View Solution play_arrowA) 2 done clear
B) 3 done clear
C) 1 done clear
D) 0 done clear
View Solution play_arrowquestion_answer11) If \[\frac{2}{5}(5x+1)+\frac{3}{5}=1,\] then what is the value of x?
A) \[\frac{-1}{5}\] done clear
B) 1 done clear
C) 0 done clear
D) \[\frac{1}{5}\] done clear
View Solution play_arrowquestion_answer12) If \[\frac{9}{5}\] of a number is 45, what is \[\frac{1}{5}\] of the same number?
A) 5 done clear
B) 25 done clear
C) 30 done clear
D) 81 done clear
View Solution play_arrowquestion_answer13) Solve for \[x:\frac{6x-2}{9}+\frac{3x+5}{18}=\frac{1}{3}.\]
A) \[\frac{1}{3}\] done clear
B) \[\frac{2}{3}\] done clear
C) \[\frac{3}{5}\] done clear
D) \[\frac{8}{3}\] done clear
View Solution play_arrowquestion_answer14) Which of the following statement do not hold in solving the equation\[15+3x=3\]?
A) \[3x=3-15\] done clear
B) \[15-3=-3x\] done clear
C) \[15+\frac{3x}{3}=3\] done clear
D) \[\frac{15}{3}+\frac{3x}{3}=\frac{3}{3}\] done clear
View Solution play_arrowA) \[2x+5=15\] done clear
B) \[7x+2=10\] done clear
C) \[5x+4=16\] done clear
D) \[3x+4=16\] done clear
View Solution play_arrowA) \[2x+3=45\] done clear
B) \[3x+2=45\] done clear
C) \[6x+3=45~\] done clear
D) \[5x+1=45~\] done clear
View Solution play_arrowA) \[3x+1=50\] done clear
B) \[x+1=20~\] done clear
C) \[6x+2=50\] done clear
D) \[2x+1=20\] done clear
View Solution play_arrowA) 42 done clear
B) 21 done clear
C) 40 done clear
D) 62 done clear
View Solution play_arrowA) \[6m+4=65\] done clear
B) \[4m+65=6\] done clear
C) \[4m+6=65\] done clear
D) \[6m+65=4\] done clear
View Solution play_arrowA) 3, 4 done clear
B) 4, 3 done clear
C) 2, 3 done clear
D) 3, 2 done clear
View Solution play_arrowStep 1: Let the unit's digit be x |
Step 2: Then, ten's digit \[=(9-x)\] \[\therefore \] Number \[=10\times (9-x)+x\] \[\Rightarrow \] \[90-10x+x=(90-9x)\] |
Step 3: Adding 27 to the number \[90-9x,\] we get \[117-9x~\] |
Step 4: Number with digits interchanged is \[10x+(9-x)=9x+9\] |
Step 5: \[117-9x=9x+9\] |
Step 6: Therefore unit's digit = 6 and ten's digit = 3 |
Step 7: Hence the number = 36. |
A) Only Step 4 done clear
B) Both Step 1 and Step 2 done clear
C) Step 1, 2, 3 and 4 done clear
D) All steps are correct done clear
View Solution play_arrowquestion_answer22) Select the INCORRECT statement.
A) In an equation, to maintain the balance or equality, any number added to one side must also be added to the other side. done clear
B) Anything subtracted from one side of an equation must also be subtracted from the other side. done clear
C) If one side of an equation is multiplied by a number, the other side must also be multiplied by the same number. done clear
D) If one side of an equation is divided by a number, the other side must also be multiplied by the same number. done clear
View Solution play_arrowA)
(a) | (b) | (c) |
\[2l\] | \[l+2l=45\] | \[10,35\] |
B)
(a) | (b) | (c) |
\[2l\] | \[l+2l=45\] | \[15,30\] |
C)
(a) | (b) | (c) |
\[l+2\] | \[45+l+2=l\] | \[15,30\] |
D)
(a) | (b) | (c) |
\[ll2\] | \[45+l/2-l=0\] | \[25,20\] |
(i) the equation formed is |
(ii) the number of 1st prizes are |
(iii) the number of 2nd prizes are |
A)
(i) | (ii) | (iii) |
\[2500x+1500(40-x)=85000\] | 25 | 15 |
B)
(i) | (ii) | (iii) |
\[2500x-1500(40-x)=85000\] | 36 | 4 |
C)
(i) | (ii) | (iii) |
\[2500x\times 1500(x-40)=85000\] | 20 | 20 |
D)
(i) | (ii) | (iii) |
\[2500x-1500(x-40)=85000\] | 15 | 25 |
question_answer25) Match the following.
Column-l | Column-II |
(i) Arjun's father's age is 5 years more than four times Arjun's age. Find Arjun's age, if his father is 37 years old. | (p) 9 |
(ii) Ramesh says that he has 8 notebooks more than four times the number of notebooks Anuj has. Ramesh has 48 notebooks. How many notebooks does Anuj have? | (q) 8 |
(iii) Varun says that he has 11 erasers more than five times the number of erasers erasers. How many erasers does Sameer have? | (r) 10 |
A) (i)\[\to \] (q). (ii)\[\to \] (p), (iii) \[\to \] (r) done clear
B) (i) \[\to \](q), (ii)\[\to \] (r), (iii) \[\to \](p) done clear
C) (i) \[\to \] (p), (ii) \[\to \] (q), (iii) \[\to \] (r) done clear
D) (i) \[\to \] (p), (ii) \[\to \] (r), (iii) \[\to \] (q) done clear
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