A) 1
B) 2
C) 1.67
D) 1.5
Correct Answer: D
Solution :
\[{{C}_{v}}=\frac{3}{2}RT;\,\,{{C}_{p}}=\frac{5}{2}RT\]for monoatomic gas \[{{C}_{v}}=\frac{5}{2}\text{RT;}\,{{C}_{p}}=\frac{7}{2}RT\] for diatomic gas Thus for mixture of 1 mole each, \[{{C}_{v}}=\frac{\frac{3}{2}RT+\frac{5}{2}RT}{2}\] and \[{{C}_{p}}=\frac{\frac{5}{2}RT+\frac{7}{2}RT}{2}\] Therefore, \[{{C}_{p}}/{{C}_{v}}=\frac{3RT}{2RT}=1.5\].
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