JEE Main & Advanced Chemistry Thermodynamics / रासायनिक उष्मागतिकी Question Bank 2nd and 3rd law of thermodynamics and Entropy

  • question_answer
    If the enthalpy of vaporization for water is 186.5 kJ \[mo{{l}^{-1}}\], the entropy of its vaporization will be [CPMT 1988; DCE 2000]

    A)                 \[0.5\,J{{K}^{-1}}mo{{l}^{-1}}\]

    B)                 \[1.0\,J{{K}^{-1}}mo{{l}^{-1}}\]

    C)                 \[1.5\,J{{K}^{-1}}mo{{l}^{-1}}\]

    D)                 \[2.0\,J{{K}^{-1}}mo{{l}^{-1}}\]

    Correct Answer: A

    Solution :

              \[\Delta {{S}_{vap}}=186.5/373=0.5\,\,J{{K}^{-1}}\,mo{{l}^{-1}}\].


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