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JEE Main & Advanced Chemistry Thermodynamics / रासायनिक उष्मागतिकी Question Bank 2nd and 3rd law of thermodynamics and Entropy

  • question_answer
    The  \[\Delta S\] for the vaporisation of 1 mol of water is 88.3  J/mole K. The value of \[\Delta S\] for the condensation of  1 mol of vapour will be

    A)                 88.3 J/mol K       

    B)                 \[{{(88.3)}^{2}}\] J/mol K

    C)                 ? 88.3 J/mol K   

    D)                 \[\frac{1}{88.3}\] J/mol K

    Correct Answer: C

    Solution :

              For reverse reaction sign will be change.


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