question_answer

Bond angle in \[{{H}_{2}}S\] is lower than in \[{{H}_{2}}O\]. Justify.

Answer:

                Bond angle in \[{{H}_{2}}O(104\cdot 5{}^\circ )\] is higher than the bond angle in\[{{H}_{2}}S(92{}^\circ )\]. The difference in the bond angles is linked with the electro negativity's of the oxygen and sulphur atoms . Since oxygen is more electronegative than sulphur therefore, the electron density around     oxygen m \[{{H}_{2}}O\] is more than around sulphur in \[{{H}_{2}}S\]. As a result, the bond angle in \[{{H}_{2}}O\]is more than the bond angle in \[{{H}_{2}}S\]