Answer:
Iodine is covalent in nature and
therefore, it does not dissolve in water which is polar. In \[KI\] solution,
iodine reacts to form \[K{{I}_{3}}\] which is ionic in nature. Therefore, it
becomes soluble in water.
\[KI+{{I}_{2}}\xrightarrow{\,}\,K{{I}_{3}}\,(\overset{+}{\mathop{K}}\,{{I}^{-}}_{3})\]
.
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