12th Class Chemistry Surface Chemistry / सतह रसायन Question Bank 12th CBSE Chemistry Surface Chemistry

  • question_answer
    Critical temperature of \[{{N}_{2}},\,CO\] and \[C{{H}_{4}}\] are 126, 134 and 190 K respectively. Arrange them in increasing order of adsorption on the surface of activated charcoal.

    Answer:

                    Critical temperature may be defined as the minimum temperature above which a gas cannot be liquefied however large its pressure may be. It may be noted that greater the critical temperature, easier will be the ease of liquefication of the gas and more will be its extent of adsorption on a particular solid such as activated charcoal. Therefore the increasing order of the extent of adsorption is:                                          \[{{N}_{2}}<CO<C{{H}_{4}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner