Answer:
These can be distinguished by
Liebermann nitrosoamine reaction. \[{{(C{{H}_{3}})}_{2}}NH\] (dimethylamine) on
treatment with \[HN{{O}_{2}}\] (generated in situ by the action of dil. \[HCl\]
on \[NaN{{O}_{2}}\]) gives yellow coloured oily N-nitrosodimethylamine.
\[\underset{\text{Dimethylamine}}{\mathop{{{(C{{H}_{3}})}_{2}}NH}}\,+HO-N=O\xrightarrow{\,}\]\[\underset{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\text{N-Nitrosodimethylamine}}{\mathop{{{(C{{H}_{3}})}_{2}}N-N=O\,}}\,\,+{{H}_{2}}O\]
N-Nitrosodimethylamine on warning with a
crystal of phenol and conc. \[{{H}_{2}}S{{O}_{4}}\] gives a green solution which when made alkaline with aqueous
\[NaOH\] turns deep blue and then red on dilution.
\[{{(C{{H}_{3}})}_{3}}N\]
(trimethylame), on the other hand being a \[3{}^\circ \] amine does not give
this test.
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