Answer:
Nitration of aniline with a nitrating
mixture consisting of conc. \[HN{{O}_{3}}\] and conc. \[{{H}_{2}}S{{O}_{4}}\]gives m-nitroaniline as the
product in very small proportions. A major portion of aniline is converted into
a black tarry mass due to partialoxidation of the ring. Under strongly acidic
conditions, aniline is protonated to form a cation which deactivates the ortho
and para positions in the ring. The nitration occurs at the meta position.
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