Answer:
(i) For the sample halogen atom, the
boiling points of \[1{}^\circ \] alkyl halides with the increase in the number
of carbon atoms in the alkyl chain due a corresponding increase in the surface
area and hence van der Waals forces of attraction. Thus b.p. of 1-Chlorobutane
(351.5 K) is higher than 1-Chloropropane (320 K).
(ii) For the same halogen atom, the b.p. of \[2{}^\circ \]
alkyl halides is lower than the corresponding 1 alkyl halide due to a
corresponding decrease in surface area and hence van der Waals forces of
attraction. Thus, b.p. of isopropyl chloride (309 K) is lower than
1-Chloropropane (320 K).
Thus, the b.p. of the three alkyl halides increase in the
order :
Isopropyl chloride < 1-Chloropropane < 1-Chlorobutane
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