Answer:
\[\underset{\text{Propene}}{\mathop{C{{H}_{3}}-CH=C{{H}_{2}}}}\,\xrightarrow[\text{(Anti-Mark}\text{.}\,\text{or}\,\text{addition)}]{\text{HBr,}\,\text{peroxide}}\] \[\underset{1-Bromopropane\,\,(X)}{\mathop{C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}-Br}}\,\xrightarrow[\text{(Finkelstein}\,\,\text{reaction)}]{\text{NaI,}\,\text{acetone}}\]\[\underset{\text{1-Iodopropane}}{\mathop{C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}-I}}\,\]
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