Answer:
Due to stronger -\[I\]-effect of F
than \[Cl,\,CH{{F}_{3}}\]should be more acidic than \[CHC{{l}_{3}}\]. But
actually reverse is true. This is due to the reason that : \[CCl_{3}^{-}\] left
after the removal of a proton from \[CHC{{l}_{3}}\] is stabilized by resonance
due to the presence of d-orbitals on \[Cl\] but: \[CF_{3}^{-}\] left after the
removal of a proton from \[CH{{F}_{3}}\] is not stabilized by resonance due to
the absence of d-orbitals on F.
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