Answer:
The first compound is a \[2{}^\circ
\] alkyl halide while all others are \[3{}^\circ \] alkyl halides. Since \[3{}^\circ
\] alkyl halides are more reactive than \[2{}^\circ \] alkyl halides in \[{{S}_{N}}1\]
reactions, therefore, first compound is the least reactive. Further reactivity
increases in the order: chloride < bromide < iodide. Thus, the increasing
order of reactivity in\[{{S}_{N}}1\] reactions is the same in which they are
listed above.
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