Answer:
Two products are formed in this reaction
\[\underset{\text{2-Bromo-3-methylbutane}}{\mathop{C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ Br \end{smallmatrix}}{\mathop{C}}\,H-\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\mathop{C}}\,H-C{{H}_{3}}}}\,\xrightarrow{{{C}_{2}}{{H}_{5}}^{-}O\overset{+}{\mathop{N}}\,a}\] 
Mechanism:
Please note that the tetiary carbocation formed as a result of 1, 2-hydride ion shift is more stable than the secondary carbocation.
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