Answer:
D-glucose exists in two cyclic
forms \[\alpha \]- and \[\beta \]- in which the aldehydic group is involved in
the formation of a ring and is not free. Therefore, it does not react with\[NaHS{{O}_{3}}.\]However,
with reagents like HCN and phenylhydrazine, the ring structure cleaves and the
aldehydic group becomes free. Therefore, D-glucose does react with HCN.
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