Answer:
In the acetone molecules, \[\alpha
\]-hydrogen atoms are to be replaced as \[{{H}^{+}}\]ions by the \[{{I}^{+}}\]
ions made available by hypoiodite\[\text{(say}\,\,\text{NaOI)}\]. Iodine being
non-polar in nature, does not provide \[{{I}^{+}}\] ion for the attack.
\[\underset{\begin{smallmatrix}
\\
\text{Acetone}
\end{smallmatrix}}{\mathop{C{{H}_{3}}COC{{H}_{3}}}}\,+\underset{\begin{smallmatrix}
\\
\text{Hypoiodite}\,\,\text{ion}
\end{smallmatrix}}{\mathop{3I{{O}^{-}}}}\,\,\xrightarrow{\,}\,\underset{\begin{smallmatrix}
\\
\text{Tri-iodoacetone}
\end{smallmatrix}}{\mathop{C{{I}_{3}}COC{{H}_{3}}}}\,+3O{{H}^{-}}\]
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