Answer:
By iodoform test. 1-Phenylethanol
contains the grouping \[-CHOH-C{{H}_{3}}\] linked to carbon and hence gives
iodoform test while 2- phenylethanol does not contain the grouping \[-CHOH-C{{H}_{3}}\]
and hence does not give iodoform test.
\[\underset{\text{1-Phenylethanol}}{\mathop{{{C}_{6}}{{H}_{5}}-CHOH-C{{H}_{3}}}}\,\xrightarrow{{{I}_{2}}/NaOH}\underset{\text{Iodoform}}{\mathop{CH{{I}_{3}}}}\,\,\,\,\,;\]
\[\underset{\text{2-Phynylethanol}}{\mathop{{{C}_{6}}{{H}_{5}}C{{H}_{2}}C{{H}_{2}}OH}}\,\xrightarrow{{{I}_{2}}/NaOH}No\,reaction\]
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