Answer:
\[C{{H}_{3}}-\underset{\text{But-2-en-1-ol}}{\mathop{CH=CH-C{{H}_{2}}}}\,-OH\xrightarrow{{{H}^{+}}}\,\]\[C{{H}_{3}}-CH=CH-C{{H}_{2}}-\overset{\oplus }{\mathop{O}}\,{{H}_{2}}\]
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