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11th Class Physics Work, Energy, Power & Collision / कार्य, ऊर्जा और शक्ति Question Bank 11th CBSE Physics Work, Energy, Power & Collision

  • question_answer
    The momentum of a body is increased by 50%. What is the percentage change in its K.E.?

    Answer:

                    When momentum is increased by 50% velocity increases by 50% i.e. velocity becomes 3/2 times; K.E becomes 9/4 times, i.e.\[\frac{9}{4}\] × 100 = 225 %. Hence increase in K.E. = 225 ? 100 = 125%


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