11th Class Physics Work, Energy, Power & Collision / कार्य, ऊर्जा और शक्ति Question Bank 11th CBSE Physics Work, Energy, Power & Collision

  • question_answer
    What is the minimum energy released in the annhilation of an electron positron pair?

    Answer:

                    The rest mass of an electron or positron is \[{{\text{m}}_{0}}=\text{9}.\text{1}\times \text{1}{{0}^{-\text{31}}}\text{kg}\]. In the annhilation of an electron positron pair, the rest mass of the two particles is converted into energy. Minimum energy released, \[E=2{{m}_{0}}{{c}^{2}}=2\left( 9.1\times {{10}^{-31}} \right){{\left( 3\times {{10}^{8}} \right)}^{2}}joule\] \[\text{E }=\frac{2\times 9.1\times 9\times {{10}^{-15}}}{1.602\times {{10}^{-13}}}MeV=1.02\,MeV\]


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