question_answer

What is the angle between and , if and denote the adjacent sides of a parallelogram drawn from a point and the area of the parallelogram is \[\frac{1}{2}AB\].                

Answer:

Area of parallelogram =\[|\overset{\to }{\mathop{A}}\,\times \overset{\to }{\mathop{B}}\,|=ABsin\text{ }\!\!\theta\!\!\text{ =}\frac{1}{2}AB\](Given) \[\therefore \]\[\sin \theta =\frac{1}{2}=\sin {{30}^{o}}\]or \[\theta ={{30}^{o}}\]