Answer:
The
magnitude of resultant \[\vec{R}\]of two vectors \[\vec{A}\]and \[\vec{B}\] is
given by\[\text{R}=\sqrt{{{A}^{2}}+{{B}^{2}}+2AB\cos \theta }\]; where \[\text{A}=\text{3m}\]and\[\text{B}=\text{4m}\].
Now\[\text{R }=\sqrt{{{3}^{2}}+{{4}^{2}}+2\times 3\times
4\cos \theta }\].
R will be 7 m if \[\theta =0{}^\circ \] (ii) R will be 1
metre if \[\theta =\text{18}0{}^\circ \] and (iii) R will be 5 m if\[\theta
=\text{9}0{}^\circ \].
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