question_answer

Two balls of different masses (one lighter and other heavier) are thrown vertically upwards with the same speed. Which one will pass through the point of projection in their downward direction with the greater speed?

Answer:

                We know that the slope of the velocity-time graph of an object with time axis is equal to the acceleration of the object. If a1, a2are the accelerations of the two objects A and B, then                 \[\frac{{{a}_{1}}}{{{a}_{2}}}=\frac{slope\,\,of\,\,v-t\,\,graph\,\,of\,\,object\,A}{slope\,\,of\,v-t\,graph\,\,of\,\,objects\,\,B}=\frac{\tan {{30}^{o}}}{\tan {{60}^{o}}}=\frac{1/\sqrt{3}}{\sqrt{3}}=\frac{1}{3}\]