Answer:
\[\text{v}=\text{dx}/\text{dt}=\text{kt}\]or\[\text{dx}=\text{
kt dt}\]. Integrating it, we have \[\text{x}=\frac{1}{2}\text{k}{{\text{t}}^{\text{2}}}\]when\[\text{t}=\text{3s}\],
then \[\text{x}=\frac{1}{2}\times \text{2}\times {{\text{3}}^{\text{2}}}=\text{
9 m}\]
You need to login to perform this action.
You will be redirected in
3 sec
