question_answer

A man standing on the edge of a cliff throws a stone straight up with initial speed u and then throws another stone straight down with same initial speed and from the same position. Find the ratio of the speeds, the stones would have attained when they hit ground at the base of the cliff.

Answer:

                Given,\[~\text{x }=\alpha -\beta \text{t }+\gamma {{\text{t}}^{\text{2}}}\]; Velocity, \[\text{V }=\frac{dx}{dt}=0\text{ }-\beta +\text{ 2}\gamma \text{t}\] and acceleration, \[\text{A}=\frac{dV}{dt}=\text{2}\gamma \]