question_answer

                                                       The displacement x of the body in motion is given by \[\text{x}=\text{A sin}\left( \omega t+\theta  \right)\]; Determine the time at which the displacement is maximum.

Answer:

                Displacement travelled in time \[({{t}_{1}}+{{t}_{2}})={{\upsilon }_{1}}{{t}_{1}}+{{\upsilon }_{2}}{{t}_{2}}\] \[\therefore \]  \[\text{Average velocity }=\frac{displacement}{total\,time\,taken}=\frac{{{\upsilon }_{1}}{{t}_{1}}+{{\upsilon }_{2}}{{t}_{2}}}{\left( {{t}_{1}}+{{t}_{2}} \right)}\]